x^2-3x(2x+5)=10

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Solution for x^2-3x(2x+5)=10 equation:


Simplifying
x2 + -3x(2x + 5) = 10

Reorder the terms:
x2 + -3x(5 + 2x) = 10
x2 + (5 * -3x + 2x * -3x) = 10
x2 + (-15x + -6x2) = 10

Reorder the terms:
-15x + x2 + -6x2 = 10

Combine like terms: x2 + -6x2 = -5x2
-15x + -5x2 = 10

Solving
-15x + -5x2 = 10

Solving for variable 'x'.

Reorder the terms:
-10 + -15x + -5x2 = 10 + -10

Combine like terms: 10 + -10 = 0
-10 + -15x + -5x2 = 0

Factor out the Greatest Common Factor (GCF), '-5'.
-5(2 + 3x + x2) = 0

Factor a trinomial.
-5((2 + x)(1 + x)) = 0

Ignore the factor -5.

Subproblem 1

Set the factor '(2 + x)' equal to zero and attempt to solve: Simplifying 2 + x = 0 Solving 2 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + x = 0 + -2 x = 0 + -2 Combine like terms: 0 + -2 = -2 x = -2 Simplifying x = -2

Subproblem 2

Set the factor '(1 + x)' equal to zero and attempt to solve: Simplifying 1 + x = 0 Solving 1 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + x = 0 + -1 x = 0 + -1 Combine like terms: 0 + -1 = -1 x = -1 Simplifying x = -1

Solution

x = {-2, -1}

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